这个文档描述 Django 文件访问用于文件的 API，例如用户上传的文件。较底层的API足够通用，你可以为其他目的来使用它们。如果你想处理 "static files" (JS, CSS, etc.)，可以查看 如何管理静态文件（如图片、JavaScript、CSS） 。
默认情况下，Django 使用 MEDIA_ROOT 和 MEDIA_URL 设置本地存储。下面的例子假设你在使用这些默认设置。
不过，Django 提供编写自定义 file storage systems 的方法，允许你完全自定义 Django 存储文件的位置和方式。这篇文档的后半部分描述了存储系统的工作方式。
当你使用 FileField 或 ImageField 时，Django 提供了一组处理文件的API。
考虑下面的模型，使用 ImageField 来存储照片：
from django.db import models
class Car(models.Model):
name = models.CharField(max_length=255)
price = models.DecimalField(max_digits=5, decimal_places=2)
photo = models.ImageField(upload_to="cars")
specs = models.FileField(upload_to="specs")
Any Car instance will have a photo attribute that you can use to get at
the details of the attached photo:
>>> car = Car.objects.get(name="57 Chevy")
>>> car.photo
<ImageFieldFile: cars/chevy.jpg>
>>> car.photo.name
'cars/chevy.jpg'
>>> car.photo.path
'/media/cars/chevy.jpg'
>>> car.photo.url
'http://media.example.com/cars/chevy.jpg'
car.photo 是一个 File 对象，这意味着它拥有下面所描述的所有方法和属性。
备注
文件在数据库中作为保存模型的一部分，因此在模型被保存之前，不能依赖磁盘上使用的实际文件名。
For example, you can change the file name by setting the file's
name to a path relative to the file storage's
location (MEDIA_ROOT if you are using the default
FileSystemStorage):
>>> import os
>>> from django.conf import settings
>>> initial_path = car.photo.path
>>> car.photo.name = "cars/chevy_ii.jpg"
>>> new_path = settings.MEDIA_ROOT + car.photo.name
>>> # Move the file on the filesystem
>>> os.rename(initial_path, new_path)
>>> car.save()
>>> car.photo.path
'/media/cars/chevy_ii.jpg'
>>> car.photo.path == new_path
True
To save an existing file on disk to a FileField:
>>> from pathlib import Path
>>> from django.core.files import File
>>> path = Path("/some/external/specs.pdf")
>>> car = Car.objects.get(name="57 Chevy")
>>> with path.open(mode="rb") as f:
... car.specs = File(f, name=path.name)
... car.save()
...
备注
While ImageField non-image data attributes, such
as height, width, and size are available on the instance, the
underlying image data cannot be used without reopening the image. For
example:
>>> from PIL import Image
>>> car = Car.objects.get(name="57 Chevy")
>>> car.photo.width
191
>>> car.photo.height
287
>>> image = Image.open(car.photo)
# Raises ValueError: seek of closed file.
>>> car.photo.open()
<ImageFieldFile: cars/chevy.jpg>
>>> image = Image.open(car.photo)
>>> image
<PIL.JpegImagePlugin.JpegImageFile image mode=RGB size=191x287 at 0x7F99A94E9048>
File 对象¶在内部，Django 在任何需要表示文件的时候使用 django.core.files.File 。
大部分情况下你只需要使用 Django 提供的 File （即附加到上述模型的文件或已经上传的文件）。
If you need to construct a File yourself, the easiest way is to create one
using a Python built-in file object:
>>> from django.core.files import File
# Create a Python file object using open()
>>> f = open("/path/to/hello.world", "w")
>>> myfile = File(f)
现在你可以使用 File 类的任何属性和方法。
Be aware that files created in this way are not automatically closed. The following approach may be used to close files automatically:
>>> from django.core.files import File
# Create a Python file object using open() and the with statement
>>> with open("/path/to/hello.world", "w") as f:
... myfile = File(f)
... myfile.write("Hello World")
...
>>> myfile.closed
True
>>> f.closed
True
Closing files is especially important when accessing file fields in a loop over a large number of objects. If files are not manually closed after accessing them, the risk of running out of file descriptors may arise. This may lead to the following error:
OSError: [Errno 24] Too many open files
在后台，Django将如何以及在哪里存储文件的决策委托给文件存储系统。这个对象实际上理解文件系统、打开和读取文件等。
Django's default file storage is
'django.core.files.storage.FileSystemStorage'. If you don't
explicitly provide a storage system in the default key of the
STORAGES setting, this is the one that will be used.
参阅下面内置默认文件存储系统的细节，也可以查看 如何编写一个自定义的文件存储类 来了解编写自己的文件存储系统的信息。
Though most of the time you'll want to use a File object (which delegates to
the proper storage for that file), you can use file storage systems directly.
You can create an instance of some custom file storage class, or -- often more
useful -- you can use the global default storage system:
>>> from django.core.files.base import ContentFile
>>> from django.core.files.storage import default_storage
>>> path = default_storage.save("path/to/file", ContentFile(b"new content"))
>>> path
'path/to/file'
>>> default_storage.size(path)
11
>>> default_storage.open(path).read()
b'new content'
>>> default_storage.delete(path)
>>> default_storage.exists(path)
False
查看 文件存储 API 来了解文件存储API。
Django 附带一个 django.core.files.storage.FileSystemStorage 类，这个类实现基础的本地文件系统文件存储。
例如，下面的代码将存储上传文件到 /media/photos 而会忽略你在 MEDIA_ROOT 的设置：
from django.core.files.storage import FileSystemStorage
from django.db import models
fs = FileSystemStorage(location="/media/photos")
class Car(models.Model):
...
photo = models.ImageField(storage=fs)
自定义存储系统（ Custom storage systems ）的工作方式也一样：将它们作为 storage 参数传递给 FileField 。
你可以使用callable作为 FileField 或 ImageField 的 storage 参数。它允许你在运行时修改存储参数，不同环境选择不同存储，例如。
当模型类被加载时，callable将进行判断，并返回 Storage 实例。
例如：
from django.conf import settings
from django.db import models
from .storages import MyLocalStorage, MyRemoteStorage
def select_storage():
return MyLocalStorage() if settings.DEBUG else MyRemoteStorage()
class MyModel(models.Model):
my_file = models.FileField(storage=select_storage)
In order to set a storage defined in the STORAGES setting you can
use storages:
from django.core.files.storage import storages
def select_storage():
return storages["mystorage"]
class MyModel(models.Model):
upload = models.FileField(storage=select_storage)
Support for storages was added.
12月 05, 2023